3.8.17 \(\int \sqrt {c x^2} (a+b x) \, dx\)

Optimal. Leaf size=33 \[ \frac {1}{2} a x \sqrt {c x^2}+\frac {1}{3} b x^2 \sqrt {c x^2} \]

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Rubi [A]  time = 0.01, antiderivative size = 33, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {15, 43} \begin {gather*} \frac {1}{2} a x \sqrt {c x^2}+\frac {1}{3} b x^2 \sqrt {c x^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[Sqrt[c*x^2]*(a + b*x),x]

[Out]

(a*x*Sqrt[c*x^2])/2 + (b*x^2*Sqrt[c*x^2])/3

Rule 15

Int[(u_.)*((a_.)*(x_)^(n_))^(m_), x_Symbol] :> Dist[(a^IntPart[m]*(a*x^n)^FracPart[m])/x^(n*FracPart[m]), Int[
u*x^(m*n), x], x] /; FreeQ[{a, m, n}, x] &&  !IntegerQ[m]

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin {align*} \int \sqrt {c x^2} (a+b x) \, dx &=\frac {\sqrt {c x^2} \int x (a+b x) \, dx}{x}\\ &=\frac {\sqrt {c x^2} \int \left (a x+b x^2\right ) \, dx}{x}\\ &=\frac {1}{2} a x \sqrt {c x^2}+\frac {1}{3} b x^2 \sqrt {c x^2}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 22, normalized size = 0.67 \begin {gather*} \frac {1}{6} x \sqrt {c x^2} (3 a+2 b x) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[c*x^2]*(a + b*x),x]

[Out]

(x*Sqrt[c*x^2]*(3*a + 2*b*x))/6

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IntegrateAlgebraic [A]  time = 0.02, size = 22, normalized size = 0.67 \begin {gather*} \frac {1}{6} x \sqrt {c x^2} (3 a+2 b x) \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[Sqrt[c*x^2]*(a + b*x),x]

[Out]

(x*Sqrt[c*x^2]*(3*a + 2*b*x))/6

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fricas [A]  time = 0.95, size = 20, normalized size = 0.61 \begin {gather*} \frac {1}{6} \, {\left (2 \, b x^{2} + 3 \, a x\right )} \sqrt {c x^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*(c*x^2)^(1/2),x, algorithm="fricas")

[Out]

1/6*(2*b*x^2 + 3*a*x)*sqrt(c*x^2)

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giac [A]  time = 1.05, size = 22, normalized size = 0.67 \begin {gather*} \frac {1}{6} \, {\left (2 \, b x^{3} \mathrm {sgn}\relax (x) + 3 \, a x^{2} \mathrm {sgn}\relax (x)\right )} \sqrt {c} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*(c*x^2)^(1/2),x, algorithm="giac")

[Out]

1/6*(2*b*x^3*sgn(x) + 3*a*x^2*sgn(x))*sqrt(c)

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maple [A]  time = 0.01, size = 19, normalized size = 0.58 \begin {gather*} \frac {\left (2 b x +3 a \right ) \sqrt {c \,x^{2}}\, x}{6} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)*(c*x^2)^(1/2),x)

[Out]

1/6*x*(2*b*x+3*a)*(c*x^2)^(1/2)

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maxima [A]  time = 1.32, size = 25, normalized size = 0.76 \begin {gather*} \frac {1}{2} \, \sqrt {c x^{2}} a x + \frac {\left (c x^{2}\right )^{\frac {3}{2}} b}{3 \, c} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*(c*x^2)^(1/2),x, algorithm="maxima")

[Out]

1/2*sqrt(c*x^2)*a*x + 1/3*(c*x^2)^(3/2)*b/c

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mupad [B]  time = 0.54, size = 20, normalized size = 0.61 \begin {gather*} \frac {\sqrt {c}\,\left (2\,b\,\sqrt {x^6}+3\,a\,x\,\relax |x|\right )}{6} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x^2)^(1/2)*(a + b*x),x)

[Out]

(c^(1/2)*(2*b*(x^6)^(1/2) + 3*a*x*abs(x)))/6

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sympy [A]  time = 0.22, size = 34, normalized size = 1.03 \begin {gather*} \frac {a \sqrt {c} x \sqrt {x^{2}}}{2} + \frac {b \sqrt {c} x^{2} \sqrt {x^{2}}}{3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*(c*x**2)**(1/2),x)

[Out]

a*sqrt(c)*x*sqrt(x**2)/2 + b*sqrt(c)*x**2*sqrt(x**2)/3

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